It can only be +2, or +4. So, Pb is at +2 oxidation state. Pb. You are correct that oxidation is the loss of electrons and reduction is the gaining of electrons. The total should equal when you add all oxidation numbers: Pb + (-2) = 0 ----> Pb = +2. Lead, being a metal, has very set oxidation numbers. But Sulfate ion has -2 charge. PbSO 4 salt does not have an overall charge. Identify the products and the reactants, and then their oxidation numbers. Pb in PbSO4 : +2. what is the oxidation number of pb in pbso4. The rates of PbSO4 formation on the Pb–0.08 mass% Ca–Sn alloys, which are the choice materials for grids in the valve-regulated lead–acid battery (VRLA), were inhibited by the presence of Sn. In order to make the compound neutral, Pb must be +2. If you consider oxidation as the loss of electrons and gain of oxidation number, and reduction as the gain of electrons and decrease in oxidation number, the oxidation states are as follows: Pb : 0 (Elementary state) H in H2SO4 : +2. Check to see if the oxidation numbers show oxidation or reduction. Therefore x+6-8=0. Oxidation number of O=-2. Could you tell me how you went about getting the oxidation number for Pb in PbSO4? Identify which reactants are being oxidized (the oxidation number increases when it reacts) and which are being reduced (the oxidation number goes down). SO4 has charge of -2. Identify the substance oxidised, reduced, oxidising agent and reducing agent for each of the following reactions: Pb(s) + PbO 2 (s) + 2H 2 SO 4 (aq) → 2PbSO 4 (s) + 2H 2 O(l) ... Pb PbO2 PbSO4 H2O H2SO4. Asked by | 25th Mar, 2009, 06:56: PM. The anodic oxidation of solid Pb in H 2 SO 4 to form PbSO 4 has been investigated by rotating disc, potentiostatic pulse and ac impedance measurements. Oxidation = number goes down Reduction = number goes up. Also, the answer would not be +10 if what you had said was correct (about the sulfur ion). I went by the rule of the most electronegative atom getting their typical oxidation state (so O was assigned -2 (total -8)...then S was assigned -2...and finally Pb was given +10 to balance the molecule). pb +2 s-2 + h +1 2 o-1 2 → pb +2 s +6 o-2 4 + h +1 2 o-2 b) Identify and write out all redox couples in reaction. Therefore oxidation number of Pb is +2. It is suggested that a precipitation mechanism to form PbSO 4 occurs under some conditions prior to the solid state … To neutral that -2 charge, +2 charge should be there and it is given by Pb 2+ ion. Oxidation number of Pb is +2 Oxidation number of S=+6. How to calculate oxidation number of Pb in PbSO4?And Explain? Therefore oxidation number of Pb in PbSO 4 … The system is compared with measurements on Pb(Hg) in H 2 SO 4 and with Pb(Hg), Hg, solid Pb in HClO 4 solution. H2O2 + PbS --> PbSO4 + H2O. Sulfide ion is at -2 oxidation state. 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